Canadian Society for Medical Laboratory Science (CSMLS) Practice Exam

Disable ads (and more) with a membership for a one time $2.99 payment

Prepare for the Canadian Society for Medical Laboratory Science Exam. Study with our tailored flashcards and multiple-choice questions, complete with hints and explanations. Ace your test!

Each practice test/flash card set has 50 randomly selected questions from a bank of over 500. You'll get a new set of questions each time!

Practice this question and more.

How much of a 50% solution of boric acid is needed to make 1 L of a 10% solution?

200 mL
400 mL
500 mL
600 mL

The correct answer is: 200 mL

To determine how much of a 50% solution of boric acid is needed to make 1 L of a 10% solution, we can apply the concept of dilution and solution concentration. We start with the formula that relates the concentrations and volumes of the solutions involved. The formula to use is: C1V1 = C2V2 Where: - C1 is the concentration of the stock solution (50% in this case), - V1 is the volume of the stock solution needed, - C2 is the concentration of the desired solution (10%), - V2 is the final volume of the desired solution (1 L or 1000 mL). Setting up the equation: (50%)(V1) = (10%)(1000 mL) To find V1 (the volume of the 50% solution), we can rearrange the equation: V1 = (10% * 1000 mL) / 50% Calculating this gives: V1 = (10000/50) mL = 200 mL This indicates that 200 mL of the 50% solution is required to achieve a final concentration of 10% in 1 liter of solution